Jharkand JSSC Lab Assistant Recruitment 2022

Jharkand JSSC Lab Assistant Recruitment Online Form 2022

Author: Admin

Date of Post: 29 August 2022

Short Information about Job: JSSC Online Registration Form for the Post of Lab Assistant Recruitment 2022 has been announced by Jharkhand Staff Selection Commission, JSSC Recruitment 2022. Interested Candidates for the JSSC Recruitment can read the Notification Before the Registration Online.

Jharkand JSSC Lab Assistant Recruitment 2022

Registration are starting from July 29, 2022 and last date for the registration is September 30, 2022. There are 690 Vacancy for the JSSC Recruitment 2022. Candidates can get selection through Written Exam. JSSC Lab Assistant Recruitment Job location is in Jharkand.

Minimum age of Recruitment is 21 Years and Maximum age of Recruitment is 40 Years. From below, you can know detailed information of the Vacancy like Important Dates, Application Fee, Eligibility Details, Pay Scale, Apply Process, Notification Details, Apply form and Recruitment Official Website.

You can also Read: UPAVP AE, JE Civil / Electrical Form 2022

www.SarkariResultsin.info

Jharkhand Staff Selection Commission, JSSC

Jharkand JSSC Lab Assistant Recruitment 2022

Advt. No. 13/2022

Details of Notification


Important Dates

  • Registration Start : August 29, 2022
  • Last Date for Registration : September 28, 2022 (11:59 PM)
  • Fee Payment Last Date : September 30, 2022
  • Last Date for Photo & Sig Upload : October 02, 2022
  • Last Date for Correction: October 03 to 06, 2022
  • Exam Date : Notified Soon
  • Admit Card Available :  Notified Soon

Application Fee

  • General, EBC and BC Candidates Fee : Rs 100
  • SC and ST of JH Candidates Fee : Rs 50

Mode of Payment

  • Candidates can Pay Exam fee using Credit card, Debit card, Net banking.

Age Limit as on February 01, 2022

  • Minimum Age of Candidates : 21 Years
  • Maximum Age of Candidates : 35 Years (UR-Male)
  • Maximum Age of Candidates : 37 Years (EBC-I, BC-II-Male)
  • Maximum Age of Candidates : 38 Years (UR,  EBC-I, BC-II- Female )
  • Maximum Age of Candidates : 40 Years (SC/ ST-Male & Female)
  • Candidates should read the Notification for Extra Age Relaxation according to Rules.

JSSC Lab Assistant Vacancy details: Total 690 Posts

Stream UR EWS SC ST EBC-I BC-II Total
Physics 93 22 23 60 18 24 230
Chemistry 93 22 23 60 18 24 230
Biology 93 22 23 60 18 24 230

JSSC Lab Assistant Eligibility Details

  • Candidates should have Bachelor's degree with 50% marks in any two subjects out of Physics, Chemistry and Biology from a University / College recognized by the State Government or Central Government or University Grants Commission. For SC / ST and all categories of disabled reserved candidates, a bachelor's degree with a minimum of 45 % marks will be mandatory.
  • Candidates should Read the Notification for Extra Details.

JSSC Lab Assistant Pay Scale

  • JSSC Lab Assistant Salary : Rs 35,400 to Rs 1,12,400(Pay Level-6)

How to Apply

  • Jharkhand Staff Selection Commission, JSSC Recruitment 2022.
  • Candidates can Register August 29, 2022 to September 28, 2022.
  • Candidates should read the Notification for Recruitment about Jharkand JSSC Lab Assistant Recruitment 2022.
  • Candidates have to Fill Your Basic Details and Upload Your Photo, Sign, ID Proof and Other necessary Documents.
  • Candidates should check Your full Details Preview Before Submit Application Form.
  • If Fees are Asked so you have to Pay Required Registration Fee to Complete the Form.
  • In last take a Print Out of Submit Final Form for any Further Process.

Interested Candidates can read the Notification Before Registration Apply.

Few Important Links

Apply Online CLick Here
Brochure Download Click Here
Notification Download Click Here
Join us on Telegram Click Here
Official Website Click Here

Disclaimer: The information which is published above can be different from the Original pieces of information because this info can change anytime on government sites due to many government reasons. We are not responsible for any Error or Any mistakes. Our team try their 100% to provide you much more correct Infomation on all subjects.